SOLUTION: Are there two integers with a product of negative 16 and a sum of negative 4?

Algebra.Com
Question 896901: Are there two integers with a product of negative 16 and a sum of negative 4?
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
x*y=-16,
x+y=-4
y=-x-4
x*(-x-4)=-16
-x^2-4x+16=0
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Start with the given expression.



Factor out the GCF .



Now let's try to factor the inner expression



---------------------------------------------------------------



Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .



Now multiply the first coefficient by the last term to get .



Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?



To find these two numbers, we need to list all of the factors of (the previous product).



Factors of :

1,2,4,8,16

-1,-2,-4,-8,-16



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to .

1*(-16) = -16
2*(-8) = -16
4*(-4) = -16
(-1)*(16) = -16
(-2)*(8) = -16
(-4)*(4) = -16


Now let's add up each pair of factors to see if one pair adds to the middle coefficient :



First NumberSecond NumberSum
1-161+(-16)=-15
2-82+(-8)=-6
4-44+(-4)=0
-116-1+16=15
-28-2+8=6
-44-4+4=0




From the table, we can see that there are no pairs of numbers which add to . So cannot be factored.



===============================================================





Answer:



So simply factors to



In other words, .




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