SOLUTION: compute value of discriminant and give the number of real solutions of this quadratic equation. 2x^2-2x+1=0

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Question 896799: compute value of discriminant and give the number of real solutions of this quadratic equation.
2x^2-2x+1=0

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic





the general solution using the quadratic equation is:







So lets solve ( notice , , and )





Plug in a=2, b=-2, and c=1




Negate -2 to get 2




Square -2 to get 4 (note: remember when you square -2, you must square the negative as well. This is because .)




Multiply to get




Combine like terms in the radicand (everything under the square root)




Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




Multiply 2 and 2 to get 4




After simplifying, the quadratic has roots of


or



The discriminant is -4 and so there are no real solutions

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