SOLUTION: How would I solve for "x" in the problem "x^3=-27"?
Algebra.Com
Question 892986: How would I solve for "x" in the problem "x^3=-27"?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How would I solve for "x" in the problem "x^3=-27"?
--------
x^3 + 27 = 0
-----
Factor::
(x+3)(x^2 - 3x + 9) = 0
---
x = -3 is the Real Number solution.
------
Solve the quadratic::
x = [3 +- sqrt(9-4*9)]/2
----
x = [3 +-sqrt(-27)]/2
----
x = [3 +- 3isqrt(3)]/2
-----
x = (3/2)(1+isqrt(3)) or (3/2)(1-isqrt(3))
Those are the Complex Number solutions.
----------------
Cheers,
Stan H.
RELATED QUESTIONS
How would I solve for "x" in the problem... (answered by Alan3354)
how would i solve for x in this problem:... (answered by chessace)
How would I solve for this division problem?
(x^3 + x^2 - 10x - 6) / (x -... (answered by Alan3354)
How would I solve for x in the problem 6x-3y... (answered by jorel555,addingup)
how would one solve for x in the problem:... (answered by josmiceli,Alan3354)
How would I solve for "x" in the problem "x^(3/2)=125"?
I know the first step would be... (answered by Alan3354,MathTherapy)
How would I do this problem?... (answered by josmiceli)
how would i go about answering this question:
solve for x using logarithms:
9^2x * (answered by josmiceli)
How do I solve for x?
27 - 2(3-2x) = 26 +... (answered by jim_thompson5910)