SOLUTION: How should I go about using the discriminant to determine the number and type of solutions for 4x^2-8x+4=0 My options are one real solution, one complex solution, two real solut

Question 770033: How should I go about using the discriminant to determine the number and type of solutions for 4x^2-8x+4=0
My options are one real solution, one complex solution, two real solutions two complex solutions

Found 2 solutions by stanbon, mananth:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
determine the number and type of solutions for 4x^2-8x+4=0
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a = 4
b =-8
c = 4
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b^2 - 4ac = 64-4*4*4 = 0
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Ans: 2 equal Real Number solutions.
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Cheers,
Stan H.

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
4x^2-8x+4=0

The nature of roots depend on b^2-4ac the discriminant
a=4,b=-8,c=4
b^2-4ac
(-8)^2-4(4)(4)
64-64=0
Since b^2-4ac=0 The roots are real and equal

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