SOLUTION: For the equation x2 + 3x + j = 0, find all the values of j such that the equation has two real number solutions. Show your work.

Question 701571: For the equation x2 + 3x + j = 0, find all the values of j such that the equation has two real number solutions. Show your work.
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Assume you mean . Either know what is the discriminant, or try filling in solution to quadratic equation.

Notice if you want only Real solutions, then the square root's radicand must be positive. . Only a simple matter to find j.
-4j>=-9
j<=(9/4) [multiplied both sides by -(1/4)]
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