SOLUTION: Imaginary Numbers (3+i)(2+4i) I believe it is 5i but I am not sure

SOLUTION: Imaginary Numbers (3+i)(2+4i) I believe it is 5i but I am not sure

Algebra.Com

Question 687979: Imaginary Numbers
(3+i)(2+4i)
I believe it is 5i but I am not sure
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
(3+i)(2+4i)

3(2+4i) + i(2+4i)

6 + 12i + 2i + 4i^2

6 + 12i + 2i + 4(-1)

6 + 12i + 2i - 4

2 + 14i

So the answer is really 2 + 14i
RELATED QUESTIONS
Imaginary Numbers Subtract (-2-4i)-(6-8i) I think the answer is -8+4 but I am not... (answered by josh_jordan)

(1+2i)/(3-4i)+(2-i)/5i (answered by MathLover1,Alan3354)

Need help please because I am not sure but believe it is. Is x^2 -5x + 6/x - 3 is the... (answered by ewatrrr)

x=2+5i or x=2x-5i Write a quadratic equation that has two solutions. I believe I am... (answered by josgarithmetic)

Simplify 3-2i-4i^3 /... (answered by robertb)

Wtie with radical notation then simplify 9 to the -3/2 power I believe the answer... (answered by MathTherapy)

I would really love some help on this problem!! Use quadratic formula to solve: x^2 (answered by vleith)

I AM CONFUSED ON THIS EQUATION 9-3R=14. I BELIEVE THE ANSWER IS -21 BUT I AM NOT SURE. (answered by Alan3354,smart1)

(2-4i)/(2) (2+4i)/(-5+2i) (1-i)/(-4-6i)... (answered by jsmallt9,palanisamy)