SOLUTION: find an irratational number between .757575... and .767676...

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Question 632433: find an irratational number between .757575... and .767676...
Answer by KMST(1868) About Me  (Show Source):
You can put this solution on YOUR website!
The number 0.757575... is 75%2F99 and 0.767676... is 76%2F99.
You can figure out 0.757575... as a fraction because
if n=0.757575... , then 100n=75.757575... and subtracting one equation from the other, you get
100n-n=75 --> (100-1)n=75 --> 99n=75 --> n=75%2F99
You can figure out that 0.767676... = 76%2F99 similarly.
You can choose an integer m between 75%5E2=5625 and 76%5E2=5776
(2625%3Cm%3C5776),
and then sqrt%28m%29%2F99 will be an irrational number between 0.757575... and 0.767676... because
0.757575... = 75%2F99=sqrt%285625%29%2F99%3Csqrt%28m%29%2F99%3Csqrt%285776%29%2F99=76%2F99 = 0.767676...