SOLUTION: help me slove this question
Find the no of pairs of integer(a,b) such that a cube + a^b+ab^+b cube +1=2002
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Question 600977: help me slove this question
Find the no of pairs of integer(a,b) such that a cube + a^b+ab^+b cube +1=2002
Found 2 solutions by richard1234, Alan3354:
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
You may want to repost the question more clearly. I think you mean
^{b^3 + 1} = 2002)
but your post can be interpreted several ways.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
help me slove this question
Find the no of pairs of integer(a,b) such that a cube + a^b+ab^+b cube +1=2002
------------
What does ab^+b mean?
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