SOLUTION: Can you please assist with the following True/False question? If "a" and "b" are elements of Real Numbers, both are not equal to 0 and a^2 = b^2, then a = b. Kind regards,

Algebra ->  Algebra  -> Real-numbers -> SOLUTION: Can you please assist with the following True/False question? If "a" and "b" are elements of Real Numbers, both are not equal to 0 and a^2 = b^2, then a = b. Kind regards,      Log On

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 Question 598189: Can you please assist with the following True/False question? If "a" and "b" are elements of Real Numbers, both are not equal to 0 and a^2 = b^2, then a = b. Kind regards,Answer by solver91311(16872)   (Show Source): You can put this solution on YOUR website! Assume that the answer is False. That is, assume that if , then . Square both sides of the inequality: But this contradicts the original assumption. Therefore, reductio ad absurdum, the original assumption is false. That is to say the statement "if , then " is a false statment and perforce "if , then " must be a true statement. John My calculator said it, I believe it, that settles it