find the discriminant , and determine the number of real solutions. Then solve 3x^2+2x-6=0 a=3, b = 2, c = -6 b²-4ac = 2²-4(3)(-6) = 4+72 = 76 The discriminant is 76, which is a positive number so there are 2 real solutions. If it had been 0, there would have been 1 real solution. It it had been a negative number, there would have been 0 (no) real solution. Edwin