# SOLUTION: PLEASE HELP WITH THIS WORD PROBLEM.....THE SECOND ANGLE OF A TRIANLGE IS 30 DEGREES LESS THAN THE FIRST ANGLR. THE THIRD ANGLE IS TWICE THE SECOND ANGLE. HOW LARGE ARE THE ANGLES?

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 Question 494021: PLEASE HELP WITH THIS WORD PROBLEM.....THE SECOND ANGLE OF A TRIANLGE IS 30 DEGREES LESS THAN THE FIRST ANGLR. THE THIRD ANGLE IS TWICE THE SECOND ANGLE. HOW LARGE ARE THE ANGLES?Answer by stanbon(57213)   (Show Source): You can put this solution on YOUR website!THE SECOND ANGLE OF A TRIANLGE IS 30 DEGREES LESS THAN THE FIRST ANGLR. THE THIRD ANGLE IS TWICE THE SECOND ANGLE. HOW LARGE ARE THE ANGLES? ------------------- Let 1st angle be "x": Then 2nd angle be "x-30" And 3rd angle is 2(x-30) = 2x-60 ------------------------------------ Equation: x + x-30 + 2x-60 = 180 4x -90 = 180 4x = 270 x = 67.5 degrees ------------------------ x-30 = 37.5 degrees ------------------------ 2x-60 = 75 degrees ============================== Cheers, Stan H. ==============================