SOLUTION: find three consecutive integers such that twice the smallest is twelve more than the largest.

SOLUTION: find three consecutive integers such that twice the smallest is twelve more than the largest.

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Question 457982: find three consecutive integers such that twice the smallest is twelve more than the largest.
Answer by wilft1(217) (Show Source): You can put this solution on YOUR website!
14, 15, 16
14+14=28 28-12=16
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