# SOLUTION: solve. Approximate irrational roots to the nearest tenth. The volume V of a pyramid varies jointly as its altitude H and the area of its base. A pyramid with a nine-inch square

Algebra ->  Algebra  -> Real-numbers -> SOLUTION: solve. Approximate irrational roots to the nearest tenth. The volume V of a pyramid varies jointly as its altitude H and the area of its base. A pyramid with a nine-inch square       Log On

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 Click here to see ALL problems on real-numbers Question 44161: solve. Approximate irrational roots to the nearest tenth. The volume V of a pyramid varies jointly as its altitude H and the area of its base. A pyramid with a nine-inch square base (a square base 9 inches on each side) and an altitude of 10 inches has a volume equal to 270 in^3. Find the volume of a pyramid with an altitude of 6 inches and a square base 4 inches on each side. (units optional)Answer by fractalier(2101)   (Show Source): You can put this solution on YOUR website!The joint relationship can be expressed as V = kbh (here b = s^2) now plug in what we know to find k... 270 = k(81)(10) so that k = 1/3 Now rewrite using the new k and the data to find the new volume... V = (1/3)bh V = (1/3)(16)(6) V = 32 in^3