SOLUTION: Find the discriminant and determine the number of real solutions. Then solve. (I did it but i have a feeling its wrong. Here's the question) 4x^2+9=2x My work: 4x^2-2x+9=0

Question 380420: Find the discriminant and determine the number of real solutions. Then solve.
(I did it but i have a feeling its wrong. Here's the question)
4x^2+9=2x
My work: 4x^2-2x+9=0
a=4, b=-2, c=9
Discriminant Formula: b^2-4ac
(-2)^2-4(4)(9)
4-144=-140
-140<0
THE EQUATION THEREFORE HAS 0 REAL SOLUTIONS
Quadratic formula: x=-b�squareroot of b^2-4ac/2a
x=-(-2)� squareroot of (-2)^2-4(4)(9)/2(4)
x=2� squareroot of 4-144/8
x=2� squareroot of -140/8
x=-2/8�i squareroot of 140/8
Simplifies as: x=1/4�i squaretoot of 35/2

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You have the correct discriminant. Let's solve for 'x'.

Start with the given equation.

Subtract 2x from both sides.

Notice we have a quadratic equation in the form of where , , and

Let's use the quadratic formula to solve for x

Start with the quadratic formula

Plug in , , and

Negate to get .

Square to get .

Multiply to get

Subtract from to get

Multiply and to get .

Simplify the square root (note: If you need help with simplifying square roots, check out this solver)

or Break up the expression.

or Reduce

So the solutions are or
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