SOLUTION: Consider the equation x2 � 4x + 29 = 0. (a) Compute the discriminant, b2 � 4ac and state whether there is one real-number solution, or two different real-number soluti

Question 367602: Consider the equation x2 � 4x + 29 = 0.
(a) Compute the discriminant, b2 � 4ac and state whether there is one real-number solution, or two different real-number solutions, or two different imaginary-number solutions.

(b) Use the quadratic formula to find the exact solutions of the equation. Show work.

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
x2 � 4x + 29 = 0.
..
a=1, b = -4, c= 29
b^2-4ac= 16-116
b^2-4ac=-100
it is less than 0
so the roots are complex
...
x1=
x1=2+5i
x2=
...
x2=2-5i
...
m.ananth@hotmail.ca
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