SOLUTION: I need help with mixturee numbers. Here is an ex: A pharmacist has 20 grams of a 10% solution of alcohol. How many grams of a 6% alcohol must be added to form an 8% alcohol?

Question 357302: I need help with mixturee numbers. Here is an ex: A pharmacist has 20 grams of a 10% solution of alcohol. How many grams of a 6% alcohol must be added to form an 8% alcohol?
Found 2 solutions by Theo, ewatrrr:
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
20 grams of 10% solution.
x grams of 6% solution.
want y grams of 8% solution.

usually you will come up with 2 or more equations that need to be solved simultaneously.

in this particular problem you start off with 20 grams of 10% solution.

you are going to add x grams of 6% solution.

you want to make a total of y grams of 8% solution.

the first equation would be:

20 + x = y

the second equation would be (20*.10) + (x*.06) = (y*.08)

The first equation is telling you how many grams of total solution.

The second equation is telling you how many grams of alcohol.

if you know how to solve simultaneous equations, the rest is just an application of the rules for solving them.

I'll use substitution.

in the first equation, you know that y = 20 + x.

you can substitute for y in the second equation to get:

(20*.10) + (x*.06) = ( (20+x) *.08)

you have now reduced 1 equation in 2 unknowns to 1 equation in 1 unknown which can now be solved for the unknown.

simplify your equation to get:

2 + .06*x = 1.6 + .08*x

subtract 1.6 from both sides of the equation to get:

.4 + .06*x = .08*x

subtract .06*x from both sides of the equation to get:

.4 = .02*x

divide both sides of the equation by .02 to get:

20 = x

that's the same as x = 20.

substitute for x in the first equation to get:

y = 20 + x = 40

the total grams in the final solution should be 40 grams.

you have x = 20 and y = 40

substitute for and y in the second equation to get:

(20*.10) + (x*.06) = (y*.08) becomes:

(20*.1) + (20*.06) = (40*.08)

simplify this to get:

2 + 1.2 = 3.2 which becomes:

3.2 = 3.2 which is true, so the values of x and y should be good.

you will need 20 grams of total solution.

you will require 3.2 grams of alcohol.

2 of them will come from 20 grams of the first solution (10%).

1.2 of them will come from 20 grams of the second solution (6%)

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

Hi,
Let x represent the amount of the 6% solution. Then the final solution will be (20 + x)
.10*20gm + .06x = .08(20gm + x)
simplify and Solve
.10*20gm + .06x = .08*20gm + .08x
.10*20-.08*20 = .08x - .06x
.02*20 = .02x
20 = x
20 gm of 6% alcohol must be added to form an 8% alcohol
check your answer
.10*20 + .06*20 = .08*40 = 3.2
RELATED QUESTIONS
how many kilograms of pure alcohol must be added to 20 grams of a 10% alcohol solution to (answered by Earlsdon)
a druggist has 20 grams of a 10% solution of alchohal. how many grams of a 6% alchohal... (answered by Fombitz)
how many grams of alcohol must be added to 40 grams of a 15% alcohol solution to obtain a (answered by Fombitz)
how many grams of alcohol must be added to 40 grams of a 15% alcohol solution to obtain a (answered by jorel1380)
a pharmacist wants to mix a medicine that is 10% asprin with a medicine that is 25%... (answered by stanbon)
A pharmacist has a 10% alcohol solution and a 25% alcohol solution. How many milliliters... (answered by Alan3354)
How many grams of salt is in 30 grams of a 20% saline solution (answered by Alan3354)
I need help making this word problem into two equations. A pharmacist has a 10% alcohol... (answered by Alan3354)
Hi. I need help with mixtures I went over this topic last year in school but completely... (answered by stanbon,MathTherapy,richwmiller)