You can put this solution on YOUR website!
Let x be one integer and x+1 be the next. Now we can set up the following equation: (Note: I'm assuming your problem is "more the the integers added" otherwise it doesn't make sense)
x(x+1)=x+(x+1)+71 Rewritten as:
x^2+x=2x+72 Subtract 2x and 72 from both sides to get:
x^2-x-72=0 Now we can factor this to be:
(x-9)(x+8)=0 Solve for x:
There we go, the integers would be 9 and 10 or -8 and -7.
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