SOLUTION: I must decide if the algebraic manipulation is correct or incorrect. if it is incorrect I need to fix it or explaine why it cannot be simplified.I don't know if this is the right s

Algebra ->  Algebra  -> Real-numbers -> SOLUTION: I must decide if the algebraic manipulation is correct or incorrect. if it is incorrect I need to fix it or explaine why it cannot be simplified.I don't know if this is the right s      Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 161549: I must decide if the algebraic manipulation is correct or incorrect. if it is incorrect I need to fix it or explaine why it cannot be simplified.I don't know if this is the right spot to post but if you can help that would be great.
2/3^-x=2(3^x)=6^x
Answer by Alan3354(21600) About Me  (Show Source):
You can put this solution on YOUR website!
I must decide if the algebraic manipulation is correct or incorrect. if it is incorrect I need to fix it or explaine why it cannot be simplified.I don't know if this is the right spot to post but if you can help that would be great.
2/3^-x=2(3^x)=6^x
-------------
It's not correct.
If I interpret it correctly, it's
2%2F%283%5E%28-x%29%29, which is
2%2A3%5E%28x%29, but that's all that can be done.
6%5Ex++=+2%5Ex%2A3%5Ex