SOLUTION: How many real solutions are there to the equation shown below? x^2 + 3x + 10 = 0

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Question 145005: How many real solutions are there to the equation shown below?
x^2 + 3x + 10 = 0
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(48546) About Me  (Show Source):
You can put this solution on YOUR website!
none ; the graph is above the x axis; the discriminant is negative.
Cheers,
Stan H

Answer by jim_thompson5910(21684) About Me  (Show Source):
You can put this solution on YOUR website!

From x%5E2%2B3x%2B10 we can see that a=1, b=3, and c=10


D=b%5E2-4ac Start with the discriminant formula


D=%283%29%5E2-4%281%29%2810%29 Plug in a=1, b=3, and c=10


D=9-4%281%29%2810%29 Square 3 to get 9


D=9-40 Multiply 4%281%29%2810%29 to get %284%29%2810%29=40


D=-31 Subtract 40 from 9 to get -31


Since the discriminant is less than zero, this means that there are two complex solutions. In other words, there are no real solutions.