SOLUTION: How do I solve using the square root and radical sign? n^2-4n-4=0

Algebra ->  Algebra  -> Real-numbers -> SOLUTION: How do I solve using the square root and radical sign? n^2-4n-4=0      Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 144930This question is from textbook prentice hall algebra 1
: How do I solve using the square root and radical sign?
n^2-4n-4=0This question is from textbook prentice hall algebra 1

Answer by stanbon(48545) About Me  (Show Source):
You can put this solution on YOUR website!
solve using the square root and radical sign?
n^2-4n-4=0
n = [4 +- sqrt(16-4*1*-4)]/2
n = [4 +- 4sqrt(2)]/2
n = [2 +- 2sqrt(2)]
===========================
Cheers,
Stan H.