SOLUTION: How do I solve using the square root and radical sign?
n^2-4n-4=0
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Question 144930This question is from textbook prentice hall algebra 1
: How do I solve using the square root and radical sign?
n^2-4n-4=0
This question is from textbook prentice hall algebra 1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve using the square root and radical sign?
n^2-4n-4=0
n = [4 +- sqrt(16-4*1*-4)]/2
n = [4 +- 4sqrt(2)]/2
n = [2 +- 2sqrt(2)]
===========================
Cheers,
Stan H.
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