SOLUTION: I would really appreciate some help solving two problems.Thank you in advance for taking the time to help me.On these problems it says to write each answer in the form a + bi. 1)

Question 132130: I would really appreciate some help solving two problems.Thank you in advance for taking the time to help me.On these problems it says to write each answer in the form a + bi.
1) (6-i)(3+2i)
2)3i(6+4i)
Found 2 solutions by josmiceli, nycsharkman:
Answer by josmiceli(6784) (Show Source):
You can put this solution on YOUR website!
{1)
(2)
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(1) (note that )

answer
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(2)

answer

Answer by nycsharkman(136) (Show Source):
You can put this solution on YOUR website!
1) (6-i)(3+2i)
TO solve, keep in mind that i^2 = -1. We are dealing with complex numbers.
For question 1, use the FOIL METHOD.
6 times 3 = 18
6 times 2i = 12i
-i times 3 = -3i
-i times 2i = -2(i)^2
Like I said above, i^2 = -1
Then, -2(-1) = 2
We now have this:
18 + 12i - 3i + 2
Combine like terms.
9i + 20
Rearrange the terms to get 20 + 9i.
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(2) 3i(6+4i)
For this question, use the distributive rule to remove the parentheses.
3i times 6 = 18i
3i times 4i = 12(i)^2
Of course, i^2 = -1 and so, 12(i)^2 = -12
We now have this:
18i - 12
Rearrange the terms and we get:
-12 + 18i
That's it!