# SOLUTION: could someone please help me with this problem? (3-i) / (1+i) I know you use the conjugate and multiply by (3-i) / (1+I) I think,but I don't think I did something right.Thanks

Algebra ->  Algebra  -> Real-numbers -> SOLUTION: could someone please help me with this problem? (3-i) / (1+i) I know you use the conjugate and multiply by (3-i) / (1+I) I think,but I don't think I did something right.Thanks       Log On

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 Click here to see ALL problems on real-numbers Question 131945: could someone please help me with this problem? (3-i) / (1+i) I know you use the conjugate and multiply by (3-i) / (1+I) I think,but I don't think I did something right.Thanks for your help in advance. Sincerely,LHAnswer by solver91311(16877)   (Show Source): You can put this solution on YOUR website!A conjugate of a complex number is formed by changing the sign on the imaginary part. So the conjugate of is . To simplify an expression with a complex denominator, you need to multiply the entire expression by 1 in the form of the conjugate of the denominator divided by itself. That means if you have , you want to multiply by 1 in the form of . Your problem: The conjugate of the denominator is , so you need to multiply the entire expression by , thus: Now multiply numerator times numerator and denominator times denominator just like multiplying any other pair of fractions. Using FOIL, the numerator product becomes: (remember so ) The denominator product is easier because, by using the conjugate, you have the factors of the difference of two squares, so Putting the pieces back together we have Done.