SOLUTION: {{{x^3-5x^2+8x-4=0}}}

Question 128285:
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
x^3-5x^2+8x-4=0
1 is a root (sum of coefficients is 0)
doing the division by x-1
1 -5 8 -4
1 1 -4 4
1 -4 4 0
then
x^2-4x+4=0 then (x-2)^2=0 then roots are
1 and 2(multiplicity 2)

RELATED QUESTIONS
subtract (5x^2 + 9x^4 - 2x^3 - 3) - (8x^6 - 8x^5 + x^4 -... (answered by jim_thompson5910)

5x/6+2/3-8x/9=0 (answered by ReadingBoosters)

x^3-8x^2+17x-4=0 (answered by tommyt3rd)

5(5x + 3) = 3(8x-... (answered by jim_thompson5910)

(8x + 3)(x^2 - 5x +... (answered by oscargut)

8x-3(6+x)=5x+4 (answered by jim_thompson5910)

5x^2-8x-4 (answered by mananth)