SOLUTION: Simplify and state the values of the variables where the expressions are undefined. [3c / (c^2-25)] x [(c-5) / (6c^2-3c)] / [2 / (c+5)]

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Question 1189170: Simplify and state the values of the variables where the expressions are undefined.
[3c / (c^2-25)] x [(c-5) / (6c^2-3c)] / [2 / (c+5)]

Found 3 solutions by MathLover1, ankor@dixie-net.com, greenestamps:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!












Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
Assuming it is:

right away we can see that it is undefined if c = -5, we get division by 0 in two of the fractions
rewrite this to

simplify

Cancel c-5, c+5 and 3c
=
c = -.5 also makes it undefined

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


The expression is undefined wherever the denominator of any fraction is zero, BEFORE simplifying. The given expression is



Factor each denominator....



Oberve that the values of c that make any of the denominators equal to 0 are -5, 5, 0, and 1/2.

To simplify, cancel the common factors 3, c, and (c-5) in the numerator of the complex fraction...



... then "flip and multiply":



ANSWER: = ; c not equal to -5, 5, 0, or 1/2


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