SOLUTION: x2 + x + sqr root of x2 + x -2 = 0 b4 + 13b2 + 36 = 0

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Question 118260This question is from textbook Elementary and Intermediate Algebra
: x2 + x + sqr root of x2 + x -2 = 0
b4 + 13b2 + 36 = 0 This question is from textbook Elementary and Intermediate Algebra

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + x + [sqr root of (x^2 + x -2)] = 0
sqrt(x^2+x-2) = -(x^2+x)
Square both sides to get:
x^2+x-2 = x^4 + 2x^3+ x^2
x^4- 2x^3 +2 = 0
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This equation has no Real Number solutions.
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b^4 + 13b^2 + 36 = 0
(b^2+9)(b^2+4) = 0
(b+3i)(b-3i)(b-2i)(b+2i) = 0
b = -3i or b=3i or b=2i or b=-2i
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Cheers,
Stan H.