SOLUTION: Wei would like to know the height of a tall building. A 3.25m pole is 114.3m away from the foot of the building. When Wei stands in a straight line with the pole and the building h

Question 1176276: Wei would like to know the height of a tall building. A 3.25m pole is 114.3m away from the foot of the building. When Wei stands in a straight line with the pole and the building he is 118.46m from the foot of the building. Wei's eye level is 1.72m above the ground level. (You may assume that it is a straight line from Wei's eye to the top of the pole and building).
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Wei would like to know the height of a tall building.
A 3.25m pole is 114.3m away from the foot of the building.
When Wei stands in a straight line with the pole and the building he is 118.46m from the foot of the building.
Wei's eye level is 1.72m above the ground level.
(You may assume that it is a straight line from Wei's eye to the top of the pole and building).
:
Draw this out. Solve the triangles that are 1.72 meters above the surface.
The small triangle formed at the pole and eye level
the horizontal side: 118.46 - 114.3 = 4.16m and
the altitude of the triangle 3.25 - 1.72 = 1.49m
Find the angle (A) to the pole and the top of the building using the tangent
tan(A) =
A = 19.7 degrees
Find the height (h} of the building using the larger triangle
tan(19.7) =
h = tan(19.7)*118.46
h = 42.4 meters
But this triangle is 1.76 meter above the ground, therefore
42.4 + 1.76 = 44.175 meters is the height of the building
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