You can
put this solution on YOUR website!I tried to look for something useful to help with this problem.
I made 7xy equal to (700 + 10x + y).
I made 4z equal to (40 + z).
Then multiplied those together to get
That didn't inspire any great thoughts.
In the end I worked up a simple EXCEL spreadsheet that cycled through the available numbers until it worked.
A less than elegant solution.
I'm not sure of the benefit of the exercise.
But here's the answer.
You can
put this solution on YOUR website!I, too, could not think of a reasonable methodology, so I hammered through the list of numbers starting with 701 and 40 using a visual basic routine to simply multiply the numbers and check the results for the presence of each of the digits. If there is a logical way to approach this, I'd like someone to share.
John
Here's the Visual Basic for Applications code that finds the answer:
Option Explicit
Sub SolveIt()
Dim i As Long
Dim j As Long
Dim Ans As Long
For i = 701 To 798
For j = 40 To 49
Ans = i * j
If OneOfEach(i, j, Ans) Then
Worksheets(1).Range("A1") = i
Worksheets(1).Range("A2") = j
Worksheets(1).Range("A3") = Ans
End If
Next j
Next i
End Sub
Function OneOfEach(Big As Long, Small As Long, Product As Long) As Boolean
Dim k As Long
Dim Complete As String
Complete = Trim(Str(Big)) & Trim(Str(Small)) & Trim(Str(Product))
For k = 0 To 9
If InStr(Complete, Trim(Str(k))) = 0 Then
OneOfEach = False
Exit Function
End If
Next k
OneOfEach = True
End Function
