SOLUTION:
Im trying to help my son, but I cant figure it out. Please Help.
Find two consecutive intergers so that the sum of the first and 3/4 of the second is 6.
Algebra.Com
Question 114601:
Im trying to help my son, but I cant figure it out. Please Help.
Find two consecutive intergers so that the sum of the first and 3/4 of the second is 6.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
LET X & (X+1) BE THE 2 CONSECUTIVE NUMBERS.
X+.75(X+1)=6
X+.75X+.75=6
1.75X=6-.75
1.75X=5.25
X=5.25/1.75
X=3 THE FIRST INTEGER.
3+1=4 FOR THE OTHER INTEGER.
PROOF
3+.75*4=6
3+3=6
6=6
RELATED QUESTIONS
Hello i need help. im not sure if i out it under the right topic
i have 3 problems i do... (answered by richwmiller)
im a parent trying to help my son figure out the process of getting to the right answer... (answered by nerdybill)
I am sorry but I am trying to help my son figure this out and just don't get it. Below... (answered by bonster)
Find 2 consecutive intergers such that the first less twice the second is equal to 98. (answered by mananth,stanbon)
Find 2 consecutive intergers such that the first less twice the second is equal to 98. (answered by nyc_function)
Is there a trick or an easy way to figure out word problems? my problem is writing out... (answered by nerdybill)
hi the type of homework i have is called " factoring complex quadratics" the equation is... (answered by josgarithmetic)
ummm im trying to solve these for homework but even if i read hoe to do the equations i... (answered by elima)
The smaller of two consecutive even intergers is five more than one half of the greater. (answered by solver91311)