SOLUTION: The height of a cannonball shot upward from a height of 14 feet above the ground with an initial velocity of 60 feet/second is given by the equation
h equals negative 16 t squ
Algebra.Com
Question 1143296: The height of a cannonball shot upward from a height of 14 feet above the ground with an initial velocity of 60 feet/second is given by the equation
h equals negative 16 t squared plus 60 t plus 14
h=−16t2+60t+14.
After how many seconds will the cannonball be 30 feet above the ground?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The height of a cannonball shot upward from a height of 14 feet above the ground with an initial velocity of 60 feet/second is given by the equation
h equals negative 16 t squared plus 60 t plus 14
h=−16t2+60t+14.
After how many seconds will the cannonball be 30 feet above the ground?
---------------------------
h(t) = −16t^2+60t+14
−16t^2+60t+14 = 30
Solve for t
RELATED QUESTIONS
The height of a cannonball shot upward from a height of 14 feet above the ground with an... (answered by Alan3354,josmiceli)
The height of a cannonball shot upward from a height of 14 feet above the ground with an... (answered by greenestamps)
The height of a cannonball shot upward from a height of 14 feet above the ground with an... (answered by josgarithmetic)
An object is shot upward from a height of 80 feet with an initial velocity of 64 feet per (answered by ankor@dixie-net.com)
An object is shot upward from a height of 96 feet with an initial velocity of 48 feet per (answered by Alan3354)
how many seconds after the cannonball was shot will it first be 1000 feet high? and how... (answered by stanbon)
if a projectile is shot vertically upward from the ground with an initial velocity of 150 (answered by Alan3354)
if a projectile is shot vertically upward from the ground with an initial velocity of 150 (answered by Alan3354,stanbon)
An object is shot upward from a height of 96 feet with an intial velocity of 48 feet per... (answered by nycsharkman)