SOLUTION: The function f is defined by f(x)= k/x +3, where k is a constant. Find k, if the graph of f passes through the point (3/4 ,0).

Algebra.Com
Question 1141345: The function f is defined by f(x)= k/x +3, where k is a constant. Find k, if the graph of f passes through the point (3/4 ,0).
Found 2 solutions by Edwin McCravy, josgarithmetic:
Answer by Edwin McCravy(20065)   (Show Source): You can put this solution on YOUR website!
We know that the equation of this graph is y = f(x) = k/x + 3,
and that it passes through the point where the black dot is on the
x-axis which is the point (3/4,0):



But we don't know what number k is in this equation:

f(x) = k/x + 3

So we change f(x) to y:

y = k/x + 3

We replace x by the x coordinate of (3/4, 0) which is 3/4 and
we replace y by the y coordinate of (3/4, 0) which is 0:

0 = k/(3/4) + 3

When we divide by a fraction we invert it and multiply:

0 = k∙(4/3) + 3

0 = (4/3)k + 3

We clear the fraction by multiplying through by the denominator 3

 3∙0 = 3∙(4/3)k + 3∙3
   0 = 4k + 9
  -9 = 4k
-9/4 = k

Edwin
Answer by josgarithmetic(39630)   (Show Source): You can put this solution on YOUR website!
---------------
The function f is defined by f(x)= k/x +3, where k is a constant. Find k, if the graph of f passes through the point (3/4 ,0).
--------------









-
Find k for point ( 3/4, 0 ).
RELATED QUESTIONS

if a graph of f(x)=-3x2+2x+k passes through the point (-1,3), then the value of k... (answered by bucky)
If the graph of f (x)=-3^2+2x+k passes through the point (-1,3) then the value of k... (answered by josgarithmetic)
The graph of a linear function that passes through the point (-2,k) and has y- intercept... (answered by josgarithmetic)
The graph of a linear function that passes through the point (-2,k) and has y- intercept... (answered by oscargut)
Let the function f be defined by y = f(x), where x and f(x) are real numbers. f(x) = 4x... (answered by richard1234,ewatrrr)
If f(x)=k(2x 3) 0 (answered by Alan3354)
{{{f(x)=3x^3-8x^2+5x-k}}} In the polynomial function above, k is a constant. If (x-2) is (answered by ikleyn)
The function f is such that f(x) = 3x - 2 for x >= 0. The function g is such that g(x) = (answered by robertb)
given the quadratic function f(x)=2x^2+kx-4r has a minimum point (k^2 - 3/4, k) where k... (answered by josgarithmetic)