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The rule of this forum is:
One and only one problem per post.
Please do not violate this rule.
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I will solve #2 for you ONLY.
The divisibility rule by 3 says:
1) an integer number is divisible by 3 if and only if the sum of its digits is divisible by 3.
2) the remainder of division of an integer number by 3 is the same as the remainder of division by 3 the sum of its digits.
The sum of digits of your number is 2+0+1+2+2+0++1+3+2+0+1+4+2+0+1+5+2+0+1+6 = 35.
This sum gives the remainder 2 when is divided by 3.
Therefore, the remainder of division the given number by 3 is 2.
Solved.