# SOLUTION: How can I solve this problem? 4c+3(2+c)=4c+6+3c =4c+3c+6

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 Click here to see ALL problems on real-numbers Question 50254: How can I solve this problem? 4c+3(2+c)=4c+6+3c =4c+3c+6 Answer by AnlytcPhil(1321)   (Show Source): You can put this solution on YOUR website!``` You are given the first two steps. You are to finish simplifying by supplying three more steps. Original expression given to simplify: 4c + 3(2 + c) = First step (given): Use distributive principle to remove parentheses 4c + 6 + 3c = Second step (given): Put the terms which contain "c" next to each other in front: 4c + 3c + 6 = Third step (not given): Use the distributive law in reverse to put c outside a parentheses with 4 + 3 inside c(4 + 3) + 6 = Fourth step (not given): Add the terms in the parentheses 4 + 3 gives 7 c(7) + 6 = Fifth step (not given) c(7) can be written as 7c 7c + 6 That is simplified as far as possible. So that's the final answer. Edwin```