# SOLUTION: !x!_> 3

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 Click here to see ALL problems on Quadratic Equations Question 45227: !x!_> 3Answer by rapaljer(4670)   (Show Source): You can put this solution on YOUR website! Do you understand that absolute value of a positive number is positive, the absolute value of 0 is zero, and the absolute value of a negative number is actually the positive number associated with it. Like absolute value of 3 is 3, absolute value of -3 is 3, absolute value of -5 is 5, etc. Be sure you understand this first. Now, draw a numberline, and by trial and error try to find the numbers on the numberline where the absolute value of the number will result in a number that is greater than or equal to 3. Trial and error results in all numbers that are from 3 on the numberline, and to the right on the numberline, like 4, 5, 6, etc. Also, trial and error results in the number -3, and all numbers to the left of -3, like -4, -5, -6, etc. This means that . In interval notation, this would be (-inf, -3] U [3, inf). R^2 at SCC In interval notation