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SOLUTION: the sum of the squares of two consecutive even integers is 1252
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Question 45043
:
the sum of the squares of two consecutive even integers is 1252
Found 2 solutions by
Nate, adamchapman
:
Answer by
Nate(3500)
(
Show Source
):
You can
put this solution on YOUR website!
Just Did This One
Answer: 24 and 26
or
Answer: -26 and -24
Answer by
adamchapman(301)
(
Show Source
):
You can
put this solution on YOUR website!
The best way to do this is trial and error:
2 squared plus 4 squared equals 20
3 squared plus 5 squared equals 34
4 squared plus 6 squared equals 52
5 squared plus 7 squared equals 74
6 squared plus 8 squared equals 100
7 squared plus 9 squared equals 130
8 squared plus 10 squared equals 164
9 squared plus 11 squared equals 202
10 squared plus 12 squared equals 244
11 squared plus 13 squared equals 290
12 squared plus 14 squared equals 340
13 squared plus 15 squared equals 394
14 squared plus 16 squared equals 452
15 squared plus 17 squared equals 514
16 squared plus 18 squared equals 580
17 squared plus 19 squared equals 650
18 squared plus 20 squared equals 724
19 squared plus 21 squared equals 802
20 squared plus 22 squared equals 884
21 squared plus 23 squared equals 970
22 squared plus 24 squared equals 1060
23 squared plus 25 squared equals 1154
24 squared plus 26 squared equals 1252
The answer is 24 and 26.
I hope this helps.
P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk
Adam