# SOLUTION: what is the equation of the quadratic function with roots -9 and and -3 and a vertex at (-6, -1).

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 Question 391027: what is the equation of the quadratic function with roots -9 and and -3 and a vertex at (-6, -1). Answer by ewatrrr(11176)   (Show Source): You can put this solution on YOUR website! ``` Hi, Parabola with vertex at pt(-6,-1) and x-intercepts are (-9,0) and (-3,0) Using the vertex form of a parabola, where(h,k) is the vertex y = a(x+6)^2 - 1 Using Pt(-3,0) to solve for a 0 = a *3^2 - 1 1 = 9a 1/9 = a y = 1/9(x+6)^2 - 1 ```