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SOLUTION: Give exact and approximate solutions to three decimal places. y^2-16y+64=36
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Question 379470
:
Give exact and approximate solutions to three decimal places.
y^2-16y+64=36
Answer by
mananth(14512)
(
Show Source
):
You can
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y^2-16y+64=36
-36
y^2-16y+64-36=0
..
y^2-16y+28
...
y^2-14y-2y+28=0
y(y-14)-2(y-14)=0
(y-14)(y-2)=0
y = 2, 14
...
m.ananth@hotmail.ca