# SOLUTION: For each of the following quadratics, A. y=-2(x+1)^2+8 B. y=x^2+6x-16 - Find the coordinates of the vertex - Direction of opening - Identify if the graph is wider o

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 Question 254215: For each of the following quadratics, A. y=-2(x+1)^2+8 B. y=x^2+6x-16 - Find the coordinates of the vertex - Direction of opening - Identify if the graph is wider or narrower than normal - Find the equation of the axis of symmetry - Find the y-intercept - Find the x-intercept - Give the domain and range for each quadratic - Draw a sketch of the quadratic. Be sure to label the vertex and axis of symmetry clearly. Use the staircase method, the x-intercepts or a point of the axis of symmetry to find the actual width of the graph.Answer by drk(1908)   (Show Source): You can put this solution on YOUR website!A. y=-2(x+1)^2+8 - Find the coordinates of the vertex vertex: (-1,8) - Direction of opening opens down because of (-) in front of 2. - Identify if the graph is wider or narrower than normal Skinny because 2 > 1 - Find the equation of the axis of symmetry Axis of symmetry is x = -1 - Find the y-intercept (0,6) - Find the x-intercept (-1,0)(-3,0) - Give the domain and range for each quadratic domain: all reals range: Y<= 8 Draw a sketch of the quadratic B. y=x^2+6x-16 FIrst we complete the square to get vertex form as: y = (X+3)^2-25 - Find the coordinates of the vertex vertex: (-3,-25) - Direction of opening opens up - Identify if the graph is wider or narrower than normal normal opening - Find the equation of the axis of symmetry axis of symmetry is x = -3 - Find the y-intercept (0,-16) - Find the x-intercept (2,0) (-8,0) - Give the domain and range for each quadratic domain: all reals range: y >= -25 - Draw a sketch of the quadratic