SOLUTION: How do you solve x^2-8x+17=0

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Question 209364: How do you solve x^2-8x+17=0
Answer by Alan3354(47455) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-8x%2B17+=+0) has the following solutons:


For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-8%29%5E2-4%2A1%2A17=-4.

The discriminant -4 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -4 is + or - sqrt%28+4%29+=+2.

The solution is x%5B12%5D+=+%28--8%2B-i%2Asqrt%28+-4+%29%29%2F2%5C1+=++%28--8%2B-i%2A2%29%2F2%5C1+, or
Here's your graph:

= 4 i