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 Question 184473: Solve: x^2 + 5x - 3 = 0 Click here to see answer by checkley77(12569)

 Question 184471: Solve the following application problem (show your equation and then your solution). Round answers to nearest thousandths and properly label your answer as well. A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 15ft by 25ft. The total area, garden plus walkway, is to be 650ft^2. What must be the width of the walkway? Click here to see answer by ankor@dixie-net.com(15645)

 Question 184470: Solve: a: (2x + 3)^2 = 5 b: 2(x - 5)^2 = 3 (mark answers a and b) Click here to see answer by kailuen(7)

 Question 184528: I'm can't figure out how to create a quadratic equation out of the vertex and a point that it must pass through. All i've managed so far is some trial and error and come up with this. y=2(x+2)²+4 From the vertex of (-2,4) and passing through (-1,8). I have been fiddling around with it and have two ideas how to proceed. I could change (x+2) to something else to move it along the x axis or change the first part of it to change the fatness or whichever you want to call it of the parabola. Regardless i figure there is a better way to do it other then trial and error, if it has been answered before i'm sorry I didn't see it. I'm self taught and this is the first time I really have had any problem. -Thanks Click here to see answer by jim_thompson5910(28536)

 Question 184533: I'm can't figure out how to create a quadratic equation out of the vertex and a point that it must pass through. All i've managed so far is some trial and error and come up with this. y=2(x+2)²+4 From the vertex of (-2,4) and passing through (-1,8). I have been fiddling around with it and have two ideas how to proceed. I could change (x+2) to something else to move it along the x axis or change the first part of it to change the fatness or whichever you want to call it of the parabola. Regardless i figure there is a better way to do it other then trial and error, if it has been answered before i'm sorry I didn't see it. I'm self taught and this is the first time I really have had any problem. -Thanks Click here to see answer by jim_thompson5910(28536)

 Question 184530: I'm can't figure out how to create a quadratic equation out of the vertex and a point that it must pass through. All i've managed so far is some trial and error and come up with this. y=2(x+2)²+4 From the vertex of (-2,4) and passing through (-1,8). I have been fiddling around with it and have two ideas how to proceed. I could change (x+2) to something else to move it along the x axis or change the first part of it to change the fatness or whichever you want to call it of the parabola. Regardless i figure there is a better way to do it other then trial and error, if it has been answered before i'm sorry I didn't see it. I'm self taught and this is the first time I really have had any problem. -Thanks Click here to see answer by jim_thompson5910(28536)

 Question 184529: I'm can't figure out how to create a quadratic equation out of the vertex and a point that it must pass through. All i've managed so far is some trial and error and come up with this. y=2(x+2)²+4 From the vertex of (-2,4) and passing through (-1,8). I have been fiddling around with it and have two ideas how to proceed. I could change (x+2) to something else to move it along the x axis or change the first part of it to change the fatness or whichever you want to call it of the parabola. Regardless i figure there is a better way to do it other then trial and error, if it has been answered before i'm sorry I didn't see it. I'm self taught and this is the first time I really have had any problem. -Thanks Click here to see answer by jim_thompson5910(28536)

 Question 184550: I'm can't figure out how to create a quadratic equation out of the vertex and a point that it must pass through. All i've managed so far is some trial and error and come up with this. y=2(x+2)²+4 From the vertex of (-2,4) and passing through (-1,8). I have been fiddling around with it and have two ideas how to proceed. I could change (x+2) to something else to move it along the x axis or change the first part of it to change the fatness or whichever you want to call it of the parabola. Regardless i figure there is a better way to do it other then trial and error, if it has been answered before i'm sorry I didn't see it. I'm self taught and this is the first time I really have had any problem. -Thanks Click here to see answer by checkley77(12569)

 Question 184560: I'm can't figure out how to create a quadratic equation out of the vertex and a point that it must pass through. All i've managed so far is some trial and error and come up with this. y=2(x+2)²+4 From the vertex of (-2,4) and passing through (-1,8). I have been fiddling around with it and have two ideas how to proceed. I could change (x+2) to something else to move it along the x axis or change the first part of it to change the fatness or whichever you want to call it of the parabola. Regardless i figure there is a better way to do it other then trial and error, if it has been answered before i'm sorry I didn't see it. I'm self taught and this is the first time I really have had any problem. -Thanks Click here to see answer by solver91311(16872)

 Question 184576: A Student did a word processing job for \$24. It took him 1 hour longer than he expected, and therefore he earned \$4 per hour less than he anaticipated. How long did he expect that it would take to do the job? Click here to see answer by ankor@dixie-net.com(15645)

 Question 184593: I'm can't figure out how to create a quadratic equation out of the vertex and a point that it must pass through. All i've managed so far is some trial and error and come up with this. y=2(x+2)²+4 From the vertex of (-2,4) and passing through (-1,8). I have been fiddling around with it and have two ideas how to proceed. I could change (x+2) to something else to move it along the x axis or change the first part of it to change the fatness or whichever you want to call it of the parabola. Regardless i figure there is a better way to do it other then trial and error, if it has been answered before i'm sorry I didn't see it. I'm self taught and this is the first time I really have had any problem. -Thanks Click here to see answer by scott8148(6628)

 Question 184612: Linear System Extension Thinking & Inquiry Questions 8. A triangle is formed by the intersection of the lines 2x+3y=14, 4x-5y=-16, and the x-axis. Find the area of the triangle Could you help me please with this question because i am really confused. Thank you very much!!! Click here to see answer by solver91311(16872)

 Question 184643: 4x^2 - 8x - 5=0 answer x= -1/2 or 5/2 need a full break down of how my text book got this answer Click here to see answer by solver91311(16872)
 Question 184643: 4x^2 - 8x - 5=0 answer x= -1/2 or 5/2 need a full break down of how my text book got this answer Click here to see answer by josmiceli(9664)

 Question 184641: 18x^2 + 9x +1=0 answer:x= -1/3 or -1/6 need a full break down of how my book got this answer Click here to see answer by ankor@dixie-net.com(15645)

 Question 184637: x^2 + 2x -5=0 answer: x= -1 +-sqrt(6) need a break down of how my book got this answer Click here to see answer by solver91311(16872)

 Question 184794: The Method of Substitution 5. On Derwin farm there is a total of 50 chickens and cows.If there are 118 legs, how many chickens are there? Can you please help with this question?? Click here to see answer by checkley77(12569)

 Question 184788: Connect English with Mathematics 1. Translate each sentence into an equation. Tell how you are assigning the two variables in each. c) Twice a number, decreased by nine, is half the same number, increased by six. Thanks. Click here to see answer by checkley77(12569)

 Question 184824: Any help with these three would be appreciated. I keep thinking I've done them correctly but was actually wrong and I've gone around with them so much I think I've completely forgotten what I'm doing! 1. 3x2 + 11x – 20 = 0 Solve by factoring 2. x2 + 3x - 4 = 0 Solve by completing the squares 3. 3x2 – x – 1 = 0 Solve by graphing (preferably using Excel) Click here to see answer by jim_thompson5910(28536)

 Question 184812: x^2 + 5x+ 4=0 answer:x=-1 or -4 need a full break down of how my text book got this answer Click here to see answer by jim_thompson5910(28536)

 Question 184810: 18x^2 +9x + 1=0 answer: x= -1/3 or -1/6 need a full break down of how my text book got this answer Click here to see answer by jim_thompson5910(28536)

 Question 184816: Solve Problems Using Linear Systems 17. Fran and Winston have a combined income of \$80 000. One quarter of Winston's income is the same as one-sixth of Fran's income. How much does each person earn? Thankssssssssss Click here to see answer by scott8148(6628)

 Question 184813: Solve Problems Using Linear Systems 15. A motor boat took 5h to travel a distance of 60 km up a river, against the current. The return trip took 3h. Find the average speed of the boat in still water and the speed of the current. Thank you sooooooo much!!!! Click here to see answer by scott8148(6628)

 Question 184809: Solve Problems Using Linear Systems 14. Mengxi has \$10 000 to invest. She invests part in a term deposit paying 5%/year, and the remainder in Canada Savings Bonds paying 3.5%/year. At the end of the year, she has earned simple interest of \$413. How much did she invest at each rate? Thank you very much>> Click here to see answer by badbadjoe(1)

 Question 184917: Give four solutions (ordered pairs) to the quadratic equation: y = -x^2 - 5x Click here to see answer by stanbon(57282)

 Question 184916: a ball is thrown vertically upward from a height of 6ft. with an initial velocity of 64ft/s, its height h after t seconds is given by h = -16t^2 + 64t + 6. How long does it take the ball to reach a height of 38 ft. on the way up? Click here to see answer by stanbon(57282)

 Question 184915: Solve: a: (2x + 3)^2 = 5 b: 2(x - 5)^2 = 3 (mark answers a and b) Click here to see answer by checkley77(12569)

 Question 184814: Solve Problems Using Linear Systems 16. One type of fertilizer has 30% nitrogen and a second type has 15% nitrogen. If a farmer needs 600kg of fertilizer that is 20% nitrogen, how much of each type should the farmer mix together? Thank you very much. Click here to see answer by checkley77(12569)

 Question 184959: x^2 + 6x -25 =0 answer: -3 +-sqrt(34) any other method of solving this equation other then viaquadratic x= -b+- sqrt(b^2-4ac)/2a need a full break down of how they got -3 +-sqrt(34) Click here to see answer by Earlsdon(6287)

 Question 185161: What is the product of the roots of this equation? 2Xsquared+ 8/9 = 3 1/3 x The answer is 4/9, but I don't know how to get there. I don't really understand the question. Thanks! Click here to see answer by vleith(2825)
 Question 185161: What is the product of the roots of this equation? 2Xsquared+ 8/9 = 3 1/3 x The answer is 4/9, but I don't know how to get there. I don't really understand the question. Thanks! Click here to see answer by checkley77(12569)