Tutors Answer Your Questions about Quadratic Equations (FREE)
Question 165753: An NFL kicker attempts a 41-yard field goal. The path of the football toward the uprights can be represented by the graph of the quadratic function f(x)= -.0625x²+2.7x, where x is the horizontal distance the football travels in yards and f(x) is the vertical distance the football travels. The bottom of the upright is 3.5 yards above the ground.
How high will the football reach its highest point? Why?
Click here to see answer by ankor@dixie-net.com(15645)  |
Question 165868: I am working on this in Applications and I can get to the last step but then I don't know how they get the answer: I have tried to multiply and add, subtract, and divide but I still can't understand the last step...
Here is and ex:
Find a negative real number such that the square of the sum of the number and 16 is equal to 36. (If there are two correct answers, either can be entered.)
I want to know how they get the number 256. this is how it is set up
x +16 squared =36
x squared + 32x+256=36
x squared + 32x = 220=0
I understand the steps except how they get the 256. Can you help me Please?
Click here to see answer by Earlsdon(6287) |
Question 165943: Here are 3 equations that I need you to check my answers on:
#1) Solve this equation in qudratic form:
y^4 + 5y^2 - 36 = 0
y^2 + 5y - 36 = 0
(y + 9)(y-4)
y +9 = 0 y-4=9
y = -9 y = 4
y^2 = -9 y^2 = 4
sqr. rt. of y^2 = +/- sqr. rt. of 9 sqr. rt. of y^2 = +/- sqr. rt. of 4
y = =/- 9i y = +/- 2
solutions are 9i, -9i, 2, -2
#2) Solve a radical equation this is reducible to a quadratic equation
sqr. rt. of x-4 + x = 6
sqr. rt. of x-4 = 6-x
(sqr. rt. of x-4)^2 = (6-x)^2
x-4 = (6-x)^2
x-4 = 36 - 6x - 6x = X^2
x-4 = x^2 - 12x + 36
0 = x^2 - 13x + 40
0 = (x-5) (x - 8)
x = 5 x = 8
5 is a solution, 8 is not.
#3) Solve a fractional equation that is reducible to a quadratic equation:
2/y+1 + 1/y-1 = 1
(y+1) (y-1) (2/y+1 + 1/y-1) = 1(y+1)(y-1)
2(y^2-1) (y+1)(y-1) + (y+1)(y-1)
Here I am stuck on this. Please help. Thanks.
Click here to see answer by Fombitz(13828)  |
Question 165978: I'm sorry if this isnt a quadratic equation...... we havent been doing algebra long so i just picked a random subject.
Here is my question (its from textbook 'Key Maths 9,3 chapter 8 section 2 homework'):
a) copy and complete : (a+b)(a-b)=
b)use the formula to simplify these
1- (s+2t)(s-2t) 2- (f+5g)(f-5g) 3-(p-3q)(p+3q)
Please help ! It said that i should include working out if possible but i dont even know how to start tackling any of this! Our maths teacher just handed us the sheet without explaining any of it
Beth x
Click here to see answer by Mathtut(3670) |
Question 166107: The height h (in feet) of an object that is dropped from the height of s feet is given by the formula h = s - 16t 2 , where t is the time the object has been falling. A 6 foot tall woman on a sidewalk looks directly overhead and sees a window washer drop a bottle from the 4 story. How long does she have to get out of the way? Round to the nearest tenth. (A story is 12 feet.) Choose the answer from the following:
2.0 seconds
1.5 seconds
1.6 seconds
1.3 seconds
Please help solve and show how to arrive at answer.
Click here to see answer by Earlsdon(6287) |
Question 166183: Please check my answers for in quadratic formula:
solve: v^2 = 12v - 24
v^2 12v + 24 = 0
v = 12 =/- sqr. rt. of 12^2 - 4(24)/2
= 12 +/- sqr. rt of 144 - 96/2
= 12 sqr. rt of 48/2
= 12 sqr. rt. of 4*4*3/2
= 12 +/- 4 sqr. rt. of 3/2
answer: 6 - 4 sqrt rt. of 3, 6 + 4 sqr. rt. of 3
Click here to see answer by Fombitz(13828)  |
Question 166189: I need to answer this question using quadratics and I am not sure where to start. Ed needs to enclose a rectangular section of his yard. The area is 35 sq ft and the perimeter is 27 ft. Find the length and the width of the section.
Click here to see answer by vleith(2825) |
Question 166189: I need to answer this question using quadratics and I am not sure where to start. Ed needs to enclose a rectangular section of his yard. The area is 35 sq ft and the perimeter is 27 ft. Find the length and the width of the section.
Click here to see answer by Mathtut(3670) |
Question 166253: An NFL kicker attempts a 41-yard field goal. The path of the football toward the uprights can be represented by the graph of the quadratic function f(x)= -.0625x²+2.7x, where x is the horizontal distance the football travels in yards and f(x) is the vertical distance the football travels. The bottom of the uprights is 3.5 yards above the ground.
The opposing team tries to block the kick by jumping with their arms and hands up in the air. If their highest reach is 3.5 yards and they are 2 yards away, will they block the kick? Why or Why not?
Click here to see answer by stanbon(57282) |
Question 166325: I am very interested in how one would derive a quadratic equation from a physical parabola. I have one that measures 3.5" from vertex to "mouth" and 4.5" across the "mouth." I plotted it on a graph with a y intercept of 3.5 and x intercepts of 2.25, -2.25. I played with your quadratic solver and a graphing calculator and the closest I was able to come to was . How could I solve this without using the aforementioned tools?
Thank you
Click here to see answer by Fombitz(13828)  |
Question 166632: An NFL kicker attempts a 41-yard field goal. The path of the football toward the uprights can be represented by the graph of the quadratic function f(x)= -.0625x²+2.7x, where x is the horizontal distance the football travels in yards and the f(x) is the vertical distance the football travels. The bottom of the uprights is 3.5 yards above the ground.
1. Assuming the kick is in between the uprights, did the kicker make the field goal? Why or Why not?
2. Would the kicker have made a 42-yard field goal with the same kick? Why or Why not?
Click here to see answer by ankor@dixie-net.com(15645)  |
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