Tutors Answer Your Questions about Quadratic Equations (FREE)
Question 65094: Find the factored form of y = 2x^2 + 6x + 4
2(x - 1)(x - 2)
(x + 1)(x + 2)
2(x - (-1))(x - (-2))
(x - (-1))(x - (-2))
Find the factored form of y = x^2 + 4
(2x - i)(2x + i)
(x - 2)(x - (-2))
(x - 2i)(x - (-2i))
(x - 0)(x - 4)
Find the usual y = ax^2 + bx + c form of the quadratic which has a = 1, and two zeros z = 3 and z' = 7
y = x^2 - 10x + 21
y = x^2 + 10x - 21
y = x^2 + 3x - 7
y = x^2 - 3x + 7
Find the usual y = ax^2 + bx + c form of the quadratic which has a = 1, and two zeros z = 2 + i and z' = 2 - i
y = x^2 - 4x + 5
y = x^2 + 4x + 5
y = x^2 + 4x - 5
y = x^2 + 4
Click here to see answer by stanbon(57352) |
Question 65129: Please help me with my take home exam.
One computer can solve a complex prime factorization problem in 75 minutes.
A second computer can solve the same problem in 50 mins. How long would
it take both computer working together to solve the problems?
Click here to see answer by Earlsdon(6287) |
Question 65237: ok here is my super dooper hard question ok ready?
a bus company has 4000 pasangers daily, each paying a fait of 2 dollars. for each 0.15$ increase the company looses about 40 passangers. if the company needs to tske in $10450 per day to stay in buisness what fare should be changed?
Click here to see answer by checkley71(8403) |
Question 63168: Use the Completing the square or Shortcut Method to find the Standard Form of the following quadratic function. Standard form: f(x) = a(x – h)2 + k
1. f(x) = x2 – 2x – 5 = __________________________
Click here to see answer by 303795(595) |
Question 65312: Suppose a cannon shoots a cannon ball into the air so that the initial upward velocity of the cannon ball is 320 feet per second.Assume the cannon ball is shot from ground level.
H=-1/2*gt^+vt+h where g is the acceleration due to gravity, and on the earth, equals 32ft/sec^ (English units) or 9.8m/sec^(metric units,
v is the initial upward velocity of the object
h is the initial height above the ground
the question:
how high will the cannon ball be in 7 seconds?
and how do you figure it out?
i tried -16x^+320*7 because i thought this is what the solver was telling me to do...my answers were 2256,2224,2128,and 2352. None of these appear to be correct. I answered question #1 by guessing: in 5 seconds, the rocket will be 1200 feet above ground. The solution I came up with was 320*5=1600, 16*5=80,then add 320+80=400, then subtract 400 from 1600 to get 1200feet, which was the correct answer , but for question #2, i am wrong if i use the same pattern.
Click here to see answer by Earlsdon(6287) |
Question 65325: how many seconds after the cannonball was shot will it first be 1000 feet high? and how many seconds will the cannonball next be 1000 feet? and how did you solve this?
scenario:suppose a cannon shoots a cannonball into the air so that the initial upward velocity of the cannonball is 320 feet per second.
formula: H=-1/2*gt^+vt+h where g is the acceleration due to gravity, and on the earth, equals 32ft/sec^, v is the initial upward velocity of the object and h is the initial height above the ground.
Click here to see answer by stanbon(57352) |
Question 65455: Can you please help me with this problem? I'm having trouble with factoring some trinomials. I tried to factor this, but I couldn't find anything that would go into 13 and 30. I don't know if that makes it prime, or if I'm doing it completely wrong. y^2+13y+30
Click here to see answer by stanbon(57352) |
Question 65507: for 1980 to 1985, the anual sales S, in thousands of dollars, of a shoe store store can be modeled by S= -0.5t^2+3t+42, where t=0 represents 1980. question: A: During which years did the store have sales of more than $50,000? B: During which year did the store achieve its max sales?"
Solving it as a quadratic is not the real question here one can find
t = 3+/-(93)^1/2.
How is this quadratic set up to relate the Sales to the time period?
One can even find the vertex of the parabola as (3, 93/2)
There is a 5 year sales (earning) period involved
S does not relate well in solving for t
There appears to be a minimum for S when t=0 in 1980 of 42
Click here to see answer by josmiceli(9680)  |
Question 64597: I really, really need help on this one..... The (-32x^2 over 310^2), in the equation below, is a fraction......
A projectile is fired from a cliff 200 feet above the water at an incline of 45 degrees to the horizontal, with a muzzle velocity of 310 feet per second. The height h of the projectile above the water is given by:
h(x)= (-32x^2 over 310^2)+x+200 , where x is the horizontal distance of the projectile from the base of the cliff. Find the maximun height of the projectile.
Click here to see answer by venugopalramana(3286) |
Question 65815: Use the quadratic formula:
3x^2-2x+1=0
I need some seriuos help on this type of problem to understand the concept and how to actually write the answer in the right form, thank you
Click here to see answer by uma(370) |
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