Tutors Answer Your Questions about Quadratic Equations (FREE)
Question 365394: Bill & Jose's Discount Cinema sold twice as many adults' tickets for $15.00 each and children's tickets for $10.00 each. Last Tuesday, a total of $1600.00 was collected from movie watchers. How many of each type of ticket were sold? (Let x represent the number of adults' tickets and y represent the number of children's tickets.)
Click here to see answer by mananth(12270)  |
Question 365901: Two cars leave an intersection. One car travels north; the other travels east.
When the car traveling north had gone 24 miles, the distance between the cars
was four miles more than three times the distance traveled by the car heading
east. Find the distance between the cars at that time.
Click here to see answer by mananth(12270)  |
Question 366142: Write a function of the form y=ax˛+bx whose graph contains the points (1,6) and (3,6).
What steps would I got through to get this answer? Would I have to graph the answer? And would i just use (1,6) as y and x, and (3,6) as a and b?
Click here to see answer by Fombitz(13828)  |
Question 366152: I need to write a quadratic function in standard form for a parabola shown. It gives me three different point on the parabola which are (2,7), (3,2), and (5,4). What is the andswer and how am I supposed to get the answer? And the parabola opens up.
Click here to see answer by Fombitz(13828)  |
Question 366485: A parabola with an equation of the form y = ax^2 + bx + c has the point (-2, 1) as its vertex. If (-4, 5) also lies on the parabola, which of the following is
another point on this parabola?
(A) (-4, 3) (B) (-1, 3) (C) (0, 5) (D) (2, 1) (E) (4, 5)
Click here to see answer by Fombitz(13828)  |
Question 366556: Evening All,
Right its been a while since i have attempted maths, and have just gone back to further ed. I have attempted the following questions, which im sure should be simple, but of course like anything its just getting back into things after a number of years. i have listed the questions below, and my answers if anybody will take the time to have a quick look and correct me where neccessary i would appreciate this.
1)Find dy/dx by differentiating with respect to x the following expressions.
a) y=x^3-6x^2+9x-1 = 3x^2-12x+8
b) y=1/2x -sqrtx = 1/2-1/2x^-1/2
c) y=e^x-e^-x = e^x+e^-x
d) y=25cosx--sinx = -25sinx-cosx
e) y= 3sinhx-4coshx = 3hsinhx+4hsinhx
f) y= (x^2+1) sinhx = 1
2 Use product rule to obtain dy/dx for the following
a) y=x^2e^x = 2x(e^x)+x^2(e^x)
b) y= xtanx = 1(tanx)+x(sec^2x)
c) y= x^4ln(x)= 4x^3(ln(x))+x^4(1/x)
d) y= x^2sinx = 2x(sinx)+x^2(cosx)
e) y= e^-xcosx = -e^-x(cos x)+ e^-x (-sinx)
f) y=(x^2+1)sinhx = (2x +1) (sinhx)+(x^2+1)(cosh x)
Finally, use the quotient rule to differentiate with respect to x, simplifying as far as possible.
a) y= sinx/1+e^-x = 1+e^-x(cosx)-(1-e^x)sinx/(1+e^-x)^2
b) y= lnx/1+x^2 = 1+x^2(1/x)-1+2x(ln x)/(1+x^2)^2
Really this would be appreciated thank you
Click here to see answer by Alan3354(30968)  |
Question 366198: Evening All, Right its been a while since i have attempted maths, and have just gone back to further ed. I have attempted the following questions, which im sure should be simple, but of course like anything its just getting back into things after a number of years. i have listed the questions below, and my answers if anybody will take the time to have a quick look and correct me where neccessary i would appreciate this.
1)Find dy/dx by differentiating with respect to x the following expressions.
a) y=x^3-6x^2+9x-1 = 3x^2-12x+8
b) y=1/2x -sqrtx = 1/2-1/2x^-1/2
c) y=e^x-e^-x = e^x+e^-x
d) y=25cosx--sinx = -25sinx-cosx
e) y= 3sinhx-4coshx = 3hsinhx+4hsinhx
f) y= (x^2+1) sinhx = 1
2 Use product rule to obtain dy/dx for the following
a) y=x^2e^x = 2x(e^x)+x^2(e^x)
b) y= xtanx = 1(tanx)+x(sec^2x)
c) y= x^4ln(x)= 4x^3(ln(x))+x^4(1/x)
d) y= x^2sinx = 2x(sinx)+x^2(cosx)
e) y= e^-xcosx = -e^-x(cos x)+ e^-x (-sinx)
f) y=(x^2+1)sinhx = (2x +1) (sinhx)+(x^2+1)(cosh x)
Finally, use the quotient rule to differentiate with respect to x, simplifying as far as possible.
a) y= sinx/1+e^-x = 1+e^-x(cpsx)-(1-e^x)sinx/(1+e^-x)^2
b) y= lnx/1+x^2 = 1+x^2(1/x)-1+2x(ln x)/(1+x^2)^2
Really this would be appreciated thank you
Click here to see answer by user_dude2008(1861) |
Question 366198: Evening All, Right its been a while since i have attempted maths, and have just gone back to further ed. I have attempted the following questions, which im sure should be simple, but of course like anything its just getting back into things after a number of years. i have listed the questions below, and my answers if anybody will take the time to have a quick look and correct me where neccessary i would appreciate this.
1)Find dy/dx by differentiating with respect to x the following expressions.
a) y=x^3-6x^2+9x-1 = 3x^2-12x+8
b) y=1/2x -sqrtx = 1/2-1/2x^-1/2
c) y=e^x-e^-x = e^x+e^-x
d) y=25cosx--sinx = -25sinx-cosx
e) y= 3sinhx-4coshx = 3hsinhx+4hsinhx
f) y= (x^2+1) sinhx = 1
2 Use product rule to obtain dy/dx for the following
a) y=x^2e^x = 2x(e^x)+x^2(e^x)
b) y= xtanx = 1(tanx)+x(sec^2x)
c) y= x^4ln(x)= 4x^3(ln(x))+x^4(1/x)
d) y= x^2sinx = 2x(sinx)+x^2(cosx)
e) y= e^-xcosx = -e^-x(cos x)+ e^-x (-sinx)
f) y=(x^2+1)sinhx = (2x +1) (sinhx)+(x^2+1)(cosh x)
Finally, use the quotient rule to differentiate with respect to x, simplifying as far as possible.
a) y= sinx/1+e^-x = 1+e^-x(cpsx)-(1-e^x)sinx/(1+e^-x)^2
b) y= lnx/1+x^2 = 1+x^2(1/x)-1+2x(ln x)/(1+x^2)^2
Really this would be appreciated thank you
Click here to see answer by Fombitz(13828)  |
Question 366578: We want to set up a business so that the minimum cost occurs when we make 13,000 items per hour at a cost of $21 per item. We also know that if we make 9,000 items per hour the cost per item is $24.
Create a quadratic equation that represents the situation. Give you final answer in the form y=ax^2+bx+c
I cannot figure out how to write anything in this form. I don't understand which each letter stands for.
Click here to see answer by jim_thompson5910(28476) |
Question 366738: I am doing quadratic equations, the problem is I understand most of it except for when I get to where the problem says x = -1 sqrt(47)/2 I don't know what to do with the square root symbol. I know how to find the vertex but I don't have the roots to graph the parabola, If some one could help me with this I would be grateful.
Click here to see answer by Alan3354(30968)  |
Question 366738: I am doing quadratic equations, the problem is I understand most of it except for when I get to where the problem says x = -1 sqrt(47)/2 I don't know what to do with the square root symbol. I know how to find the vertex but I don't have the roots to graph the parabola, If some one could help me with this I would be grateful.
Click here to see answer by jim_thompson5910(28476) |
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