SOLUTION: I still cant figure out the answer to this question even with this website. The question is: Solve by using te quadratic formula. 5x^2+4x-7=0

You can put this solution on YOUR website!
Solve by using the quadratic formula. 5x^2+4x-7=0
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a=5 ; b=4 ; c=-7
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Quadratic Formula:-----------
x = [-b + sqrt(b^2-4ac)]/[2a] or x=[-b-sqrt(b^2-4ac)]/[2a}
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Your Problem:
x = [-4 + sqrt(4^2-4*5*-7)]/[2*5] or......
x = [-4 + sqrt(156)]/[10].........or......
x= [-4 + 2sqrt(39)]/10...........or
x= [-2 + sqrt(39)]/5......or x = [-2-sqrt(39)]/5
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Cheers,
Stan H.