SOLUTION: Given f(x) = –x3 + 3x2 – x + 4, find f(–2), f(0), and f(3)

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Question 75196: Given f(x) = –x3 + 3x2 – x + 4, find f(–2), f(0), and f(3)
Answer by jim_thompson5910(21685) About Me  (Show Source):
You can put this solution on YOUR website!
To find f(-2) just replace x with -2 for every x
f%28-2%29+=+-%28-2%29%5E3+%2B+3%28-2%29%5E2+-+%28-2%29+%2B+4
f%28-2%29+=+-%28-8%29+%2B+3%284%29+%2B2+%2B+4
f%28-2%29+=+8+%2B+12+%2B6
f%28-2%29+=+26

To find f(0) just replace x with 0 for every x
f%280%29+=+-%280%29%5E3+%2B+3%280%29%5E2+-+%280%29+%2B+4
f%280%29+=+0+%2B+3%280%29+-0+%2B+4
f%280%29+=+0%2B4
f%280%29+=+4
To find f(3) just replace x with 3 for every x
f%283%29+=+-%283%29%5E3+%2B+3%283%29%5E2+-+%283%29+%2B+4
f%283%29+=+-27+%2B+3%289%29+-3+%2B+4
f%283%29+=+-27+%2B+27+%2B1
f%283%29+=+1