SOLUTION: Given a line containing the points (1,3), (2,4), (3,5) determine the slope-intercept form of the equation, give one additional point on this line and graph the function. Equati

Algebra ->  Algebra  -> Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Given a line containing the points (1,3), (2,4), (3,5) determine the slope-intercept form of the equation, give one additional point on this line and graph the function. Equati      Log On

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Question 71129: Given a line containing the points (1,3), (2,4), (3,5) determine the slope-intercept form of the equation, give one additional point on this line and graph the function.
Equation of line in slope-intercept form f(x) =

Show your work here:
Give one additional point in (x,y) form that would fall on this line: (4,6)
Graph the function:

Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
SLOPE=(Y2-Y1)/(X2-X1)
(4-3)/(2-1)=1/1=1
NOW SUBSTITUTE ONE SET OF (X,Y) POINTS AND SOLVE FOR THE Y INTERCEPT. THUS
3=1*1+b
3=1+b
b=3-1
b=2 THUS THE EQUATION OF THIS LINE IS
Y=X+2
+graph%28+200%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+x+%2B2%29+ (graph 200x200 pixels, x from -6 to 5, y from -10 to 10, y = x +2).