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= liters of 28% solution needed
Let

= liters of 14% solution needed

= liters of sulfuric acid in 28% solution

= liters of sulfuric acid in 14% solution
-------------------------------------
(1)

(2)

---------------------------
(2)

(2)

(2)

Subtract (1) from (2)
(2)

(1)

and, since
(1)

(1)

(1)

5 liters of 28% solution are needed
2 liters of 14% solution are needed
check:
(2)

(2)

(2)

(2)

(2)

OK