SOLUTION: Find two consecutive positive integers such that the sum of their squares is 85. Thank you

You can put this solution on YOUR website!
Call the numbers x and x+1.
Thus we have
x^2 + (x+1)^2 = 85
x^2 + x^2 + 2x + 1 = 85
2x^2 + 2x - 84 = 0
x^2 + x - 42 = 0
(x + 7)(x - 6) = 0
x = -7 or x = 6
but you want positive, so your numbers are
6 and 7

You can put this solution on YOUR website!
Let x and y be two consecutive numbers
so we can write y=x+1 ------>(1)
Given: ---------->(2)
Plugin equation(1) in equation(2)





x=6,x=-7
leaving the negative number so we get x=6
sofrom equation(1) we get
y=6+1=7
So the two consecutive numbers are x=6 and y=7
checking: substitute values of x and y in equation (2)


that's true!
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