SOLUTION: (2x-4)^2=20

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Question 59316: (2x-4)^2=20
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
(2X-4)^2=20
4X^2-16X+16=20
4X^2-16X+16-20=0
4X^2-16X-4=0
X^2-4X-1 USIBG THE QUADRATIC EQUATION X=(-B+-SQRT[B^2-4AC])/2A
X=(4+-SQRT[16-4^1*-1])/2*1
X=(4+-SQRT[16+4])/2*1
X=(4+-SQRT20)/2
X=(4+-4.472)/2
X=(4+4.472)/2
X=8.472/2
X=4.236 SOLUTION
X=4-4.472/2
X=-.472/2
X=-.236 SOLUTION