SOLUTION: A rectangle that the length is twice the with with an area of 50yd^2

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Question 384282: A rectangle that the length is twice the with with an area of 50yd^2
Answer by mananth(16949) About Me  (Show Source):
You can put this solution on YOUR website!
width = x
length = 2x
..
L*W=Area
2x*x=50
2x^2=50
/2
x^2=25
sqrt%28x%5E2%29=sqrt%2825%29
x= 5 yard the width
..
length = 2x = 10 yard the length
...
m.ananth@hotmail.ca